Prove that the fraction #(21n+4)/(14n+3)# is irreducible for every #n in NN#?
1 Answer
Nov 10, 2016
Calculate the GCF of
Explanation:
Calculate the GCF of
#(21n+4)/(14n+3) = 1" "# with remainder#7n+1#
#(14n+3)/(7n+1) = 2" "# with remainder#1#
#(7n+1)/1 = 7n+1" "# with remainder#0#
So the GCF is
