Points A and B are at (9 ,4 ) and (1 ,5 ), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 and dilated about point C by a factor of 3 . If point A is now at point B, what are the coordinates of point C?

1 Answer
Aug 12, 2017

The coordinates of C=(11/2,-16)

Explanation:

Point A=((9),(4)) and point B=((1),(5))

The rotation of point A counterclockwise by (3/2pi) tranforms the point A into

A'=((4),(-9))

Let point C=((x),(y))

The dilatation is

vec(CB)=3vec(CA')

((1),(5))-((x),(y))=3*((4),(-9))-((x),(y)))

Therefore,

1-x=3(4-x)

1-x=12-3x

2x=12-1=11, =>, x=11/2

5-y=3(-9-y)

5-y=-27-3y

2y=-27-5=-32, =>, y=-16

The point C=(11/2,-16)