Points A and B are at (6 ,1 ) and (8 ,9 ), respectively. Point A is rotated counterclockwise about the origin by pi and dilated about point C by a factor of 2 . If point A is now at point B, what are the coordinates of point C?

1 Answer
May 28, 2017

The point C=(-20,-11)

Explanation:

A rotation counterclockwise by pi, point A becomes A'

A=(6,1)

The coordinates of A'=(-6,-1)

Let the point C=(x,y)

So,

vec(CB)=2vec(CA')

((8-x),(9-y))=2((-6-x),(-1-y))

Therefore,

8-x=-12-2x, =>, x=-12-8=-20

9-y=-2-2y, =>, y=-2-9=-11

The point C=(-20,-11)