Points A and B are at (4 ,9 ) and (7 ,2 ), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 and dilated about point C by a factor of 1/2 . If point A is now at point B, what are the coordinates of point C?

1 Answer
May 7, 2017

The point C is (-5/3,8)

Explanation:

The matrix of a rotation counterclockwise by 3/2pi about the origin is

((0,1),(-1,0))

Therefore, the trasformation of point A is

A'=((0,1),(-1,0))((4),(9))=((9),(-4))

Let point C be (x,y), then

vec(CB)=1/2 vec(CA')

((7-x),(2-y))=1/2((9-x),(-4-y))

So,

7-x=1/2(9-x)

14-2x=9-5x

3x=9-14=-5

x=-5/3

and

2-y=1/2(-4-y)

4-2y=-4-y

y=8

Therefore,

point C=(-5/3,8)