Points A and B are at #(3 ,7 )# and #(4 ,2 )#, respectively. Point A is rotated counterclockwise about the origin by #pi # and dilated about point C by a factor of #5 #. If point A is now at point B, what are the coordinates of point C?

2 Answers
Jan 13, 2018

After Point A is rotated counterclockwise about the origin by #pi#, its new coordinates are #(-3, -7)#.

The difference between the #x# coordinates of Point A and B now is #4-(-3)=7# and #y# coordinates: #2-(-7)=9#

Since Point A was dilated about Point C by a factor of 5, we can find out by how much the coordinates change with each integer increase in factor.

For the #x# coordinate:
#7/4=1.75#
and #y# coordinate:
#9/4=2.25#

So for every integer increase in factor, the point moves 1.75 to the right and 2.25 upwards.

Point C is therefore
#(-3-1.75, -7-2.25)#
#=(-4.75, -9.25)#

Jan 13, 2018

#C=(-19/4,-37/4)#

Explanation:

#"under a counterclockwise rotation about the origin of "pi#

#• " a point "(x,y)to(-x,-y)#

#rArrA(3,7)toA'(-3,-7)" where A' is the image of A"#

#rArrvec(CB)=color(red)(5)vec(CA')#

#rArrulb-ulc=5(ula'-ulc)#

#rArrulb-ulc=5ula'-5ulc#

#rArr4ulc=5ula'-ulb#

#color(white)(4ulcxx)=5((-3),(-7))-((4),(2))#

#color(white)(xxxx)=((-15),(-35))-((4),(2))=((-19),(-37))#

#rArrulc=1/4((-19),(-37))=((-19/4),(-37/4))#

#rArrC=(-19/4,-37/4)#