Points A and B are at (2 ,4 ) and (7 ,5 ), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 and dilated about point C by a factor of 2 . If point A is now at point B, what are the coordinates of point C?

1 Answer
Jun 17, 2017

The coordinates of point C are =(1,-9)

Explanation:

The matrix of a rotation counterclockwise by 3/2pi about the origin is

((0,1),(-1,0))

Therefore, the transformation of point A is

A'=((0,1),(-1,0))((2),(4))=((4),(-2))

Let point C be (x,y), then

vec(CB)=2 vec(CA')

((7-x),(5-y))=2((4-x),(-2-y))

So,

7-x=2(4-x)

7-x=8-2x

x=1

and

5-y=2(-2-y)

5-y=-4-2y

y=-4-5

y=-9

Therefore,

point C=(1,-9)