Points A and B are at (2 ,1 )(2,1) and (4 ,7 )(4,7), respectively. Point A is rotated counterclockwise about the origin by (3pi)/2 3π2 and dilated about point C by a factor of 3 3. If point A is now at point B, what are the coordinates of point C?

2 Answers
Jun 21, 2017

The coordinates of point C=(-1/2,-13/2)C=(12,132)

Explanation:

The matrix of a rotation counterclockwise by 3/2pi32π about the origin is

((0,1),(-1,0))

Therefore, the transformation of point A is

A'=((0,1),(-1,0))((2),(1))=((1),(-2))

Let point C be (x,y), then

vec(CB)=2 vec(CA')

((4-x),(7-y))=3((1-x),(-2-y))

So,

4-x=3(1-x)

4-x=3-3x

2x=-1

x=-1/2

and

7-y=3(-2-y)

7-y=-6-3y

2y=-6-7

y=-13/2

Therefore,

point C=(-1/2,-13/2)

Jun 21, 2017

C=(-1/2,-13/2)

Explanation:

"under a counterclockwise rotation about the origin of " (3pi)/2

• " a point " (x,y)to(y,-x)

rArrA(2,1)toA'(1,-2)" where A' is the image of A"

"under a dilatation about C of factor 3"

vec(CB)=color(red)(3)vec(CA')

rArrulb-ulc=color(red)(3)(ula'-ulc)

rArrulb-ulc=3ula'-3ulc

rArr2ulc=3ula'-ulb

color(white)(rArr2ulc)=3((1),(-2))-((4),(7))

color(white)(rArr2ulc)=((3),(-6))-((4),(7))=((-1),(-13))

rArrulc=1/2((-1),(-13))=((-1/2),(-13/2))

"the components of " ulc" are the coordinates of C"

rArrC=(-1/2,-13/2)