Point A is at $(9 ,3 )$ and point B is at $(5 ,-6 )$ . Point A is rotated $pi/2$ clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

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Answer 1 · 2018-02-22T06:00:53

Decrease in distance due to rotation of point A is 6.2433

$A (9,3), B (5, -6)$ A rotated clockwise by $(pi/2)$ about origin.

$vec(AB) = sqrt((9-5)^2 + (3+6)^2) = sqrt97 = 9.8489$

$A’(x,y) = (3,-9)$

$vec(A’B) = sqrt ((3-5)^2 + (-9+6)^2) = sqrt13 = 3.6056$

Change in distance between $A’B, AB$ is

$d = 3.6056 - 9.8489 = -6.2433$

Point A is at (9 ,3 )(9 ,3 ) and point B is at (5 ,-6 )(5 ,-6 ). Point A is rotated pi/2 pi/2 clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?