Point A is at $(-5 ,-1 )$ and point B is at $(-5 ,-3 )$ . Point A is rotated $(3pi)/2$ clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

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Answer 1 · 2018-02-22T13:52:56

Increase in distance due to rotation of A is $color(blue)(d = 4.3246$

![http://www.scielo.org.za/ scielo.php

$A (-5,-1), B(-5,-3)$ A Rotated about origin by $(3pi)/2$ clockwise.

$vec(AB) = sqrt ((-5+5)^2 + (-1+3)^2) = 2$

$A ((-5),(-1)) -> A’((1),(-5))$

$vec(A’B) = sqrt ((1+5)^2 + (-5+3)^2) = 6.3246$

Increase in distance due to rotation of A is

$color(blue)(d = 6.3246 - 2 = 4.3246$

Point A is at (-5 ,-1 )(-5 ,-1 ) and point B is at (-5 ,-3 )(-5 ,-3 ). Point A is rotated (3pi)/2 (3pi)/2 clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?