Point A is at $(2 ,-6 )$ and point B is at $(-2 ,-7 )$ . Point A is rotated $(3pi)/2$ clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

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Answer 1 · 2018-02-22T13:44:10

Increase in distance due to rotation of A is $d = 9.8085$

$A (2,-6), B (-2,-7)$ . Rotated about origin by $(3pi)/2$ clockwise.

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$vec(AB) = sqrt((2+2)^2 + (-6+7)^2) = 2.2361$

$A((2),(-6)) -> A’((6),(2))$

$vec(A’B) = sqrt ((6+2)^2 + (2+7)^2) = 12.0416$

Increase in distance due to rotation of A is

$d = 12.0416 - 2.2361 = 9.8085$

Point A is at (2 ,-6 )(2 ,-6 ) and point B is at (-2 ,-7 )(-2 ,-7 ). Point A is rotated (3pi)/2 (3pi)/2 clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?