Point A is at $(-2 ,-5 )$ and point B is at $(-3 ,1 )$ . Point A is rotated $pi/2$ clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

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Answer 1 · 2016-03-04T09:30:47

New point $A(x_(a2),y_(a2))=(-5, 2)$
Difference in distance $=sqrt37-sqrt5=3.8466$

The original distance
$d=sqrt((x_(a1)-x_b)^2+(y_(a1)-y_b)^2)$

$d=sqrt((-2--3)^2+(-5-1)^2)$

$d=sqrt((1^2+(-6)^2)$

$d=sqrt(37)$

The new distance:

$d=sqrt((x_(a2)-x_b)^2+(y_(a2)-y_b)^2)$

$d=sqrt((-5--3)^2+(2-1)^2)$

$d=sqrt(4+1)$

$d=sqrt5$

God bless....I hope the explanation is useful.

Point A is at (-2 ,-5 )(-2 ,-5 ) and point B is at (-3 ,1 )(-3 ,1 ). Point A is rotated pi/2 pi/2 clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?