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Please solve q 88?

1 Answer

Jan 3, 2018

#a^2+b^2+c^2-2b+6c=-10#

#=>a^2+b^2-2b+1^2+c^2+2*c*3+3^2=0#

#=>a^2+(b-1)^2+(c+3)^2=0#

Sum of three squared quantities being zero each is zero.

So #a=0 ,b=1,c=-3#

Hence #a+b+c=0+1-3=-2#

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