Please show the integration of (x^3)/((x^4+7)^8)dx step by step?

1 Answer
May 23, 2018

We have

I = int x^3/(x^4 + 7)^8 dx

Let u = x^4 + 7dx. Then du = 4x^3 dx and dx = (du)/(4x^3)

I = int x^3/u^8 * (du)/(4x^3)

I = 1/4int u^-8 du

I = 1/4(-1/7u^-7) + C

I = -1/28(x^4 + 7)^-7 +C

Hopefully this helps!