Please help me with the logarithm applications?

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Answer 1 · 2018-01-21T11:47:38

#10.16# billion dollars a year.

#s=-254.9+121.95ln(t)#

First we need to differentiate this. This will allow us to find the instantaneous rate of change:

#(ds)/(dt)(-254.9+121.95ln(t))=121.95/t#

If #t=9# represents 1999, then for 2002:

#2002-1999=3#

#t=9+3=12#

Plugging this into our derivative:

#121.95/12=10.1625#

#10.16# billion dollars a year.