One of the sides of an equilateral triangle is 61. What is the height of the triangle?

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One of the sides of an equilateral triangle is 61. What is the height of the triangle?

geometry

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Answer 1 · 2018-02-17T05:31:22

given, $side = 61 units$ $"side = 61 units"$

$area of the triangle = \frac{\sqrt{3}}{4} {(s i d e)}^{2}$ $"area of the triangle" = color(magenta)(sqrt3/4 (side)^2$
$A = \frac{\sqrt{3}}{4} \cdot 61 \cdot 61$ $A=sqrt3/4 * 61*61$

also, $area of the triangle = \frac{1}{2} (b a s e) (h e i g h t)$ $"area of the triangle" = color(magenta)(1/2 (base)(height)$
$\frac{\sqrt{3}}{4} \cdot 61 \cdot 61 = \frac{1}{2} \cdot 61 \cdot (h e i g h t)$ $sqrt3/4 * 61*61 = 1/2 * 61 * (height)$
$\frac{\sqrt{3}}{2} \cdot 61 = (h e i g h t)$ $sqrt3/2 * 61 = (height)$

$height = \frac{61 \sqrt{3}}{4} u n i t s$ $"height" = (61sqrt3)/4 units$

-Sahar :)

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One of the sides of an equilateral triangle is 61. What is the height of the triangle?

geometry

1 Answer

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