On the figure given show that bar(OC) is sqrt(2)?

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1 Answer
Gió
Sep 14, 2016

WOW...I finally got it...although it seems too easy...and probably it is not the way you wanted it!

Explanation:

I considered the two small circles as equal and having radius 1, each of them (or u as unity in distance bar(PO)...I think). So the entire base of the triangle (diameter of big circle) should be 3.
According to this, the distance bar(OM) should be 0.5 and the distance bar(MC) should be one big cirlce radius or 3/2=1.5.
Now, I applied Pythagoras to the triangle OMC with:
bar(OC)=x
bar(OM)=0.5
bar(MC)=1.5 and I got:
1.5^2=x^2+0.5^2
or:
x^2=1.5^2-0.5^2=(3/2)^2-(1/2)^2=8/4=2
so:
x=sqrt(2)

Does it make sense...?

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