Ok so how do you solve the following equation?
#9^x=3^(x-1)#
Thanks!
Thanks!
1 Answer
Feb 7, 2017
Explanation:
#"left side "=9^x=(3^2)^x=3^(2x)#
#rArr3^(2x)=3^(x-1)larr" equation to be solved"# Since the bases are equal. That is both 3, then we can equate the exponents.
#rArr2x=x-1rArrx=-1#
#color(blue)"As a check"# Substitute this value into the equation and if the left side is equal to the right side then it is the solution.
#"left side "=9^-1=1/9#
#"right side "=3^-2=1/3^2=1/9#
#rArrx=-1" is the solution"#