Objects A and B are at the origin. If object A moves to $(- 8, 7)$ $(-8 ,7 )$ and object B moves to $(6, - 7)$ $(6 ,-7 )$ over $5 s$ $5 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

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Answer 1 · 2018-01-01T07:55:49

The relative velocity is $= < \frac{14}{5}, - \frac{14}{5} > m s^{- 1}$ $= <14/5, -14/5> ms^-1$

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The absolute velocity of $A$ $A$ is $v_{A} = \frac{1}{5} < - 8, 7 > = < - \frac{8}{5}, \frac{7}{5} >$ $v_A =1/5<-8,7> = <-8/5,7/5>$

The absolute velocity of $B$ $B$ is $v_{B} = \frac{1}{5} < 6, - 7 > = < \frac{6}{5}, - \frac{7}{5} >$ $v_B =1/5<6,-7> = <6/5,-7/5>$

The relative velocity of $B$ $B$ with respect to $A$ $A$ is

$v_{B / A} = v_{b} - v_{A}$ $v_ (B//A)=v_b-v_A$

$= < \frac{6}{5}, - \frac{7}{5} > - < - \frac{8}{5}, \frac{7}{5} >$ $=<6/5,-7/5> - <-8/5,7/5>$

$= < \frac{6}{5} + \frac{8}{5}, - \frac{7}{5} - \frac{7}{5} >$ $= <6/5+8/5, -7/5-7/5>$

$= < \frac{14}{5}, - \frac{14}{5} > m s^{- 1}$ $= <14/5, -14/5> ms^-1$

Objects A and B are at the origin. If object A moves to (−8,7)(-8 ,7 ) and object B moves to (6,−7)(6 ,-7 ) over 5s5 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.