Objects A and B are at the origin. If object A moves to $(-6 ,-2 )$ and object B moves to $(-5 ,-4 )$ over $3 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

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Answer 1 · 2016-07-07T08:29:22

$v_"AB"=sqrt5/3 " "m/s$
$"please look over the animation"$

enter image source here

$vec a:"represents velocity of B from perspective of A"$
$u:"(red vector) represents velocity of A"$
$v=u:"represents velocity of B"$

$"note that "vec a=vec w-vec u$

enter image source here

$"you need to find the relative displacement"$
$"let "Delta x" be relative displacement"$
$"please look over the figure above"$

$Delta x=sqrt(AG^2+GB^2)$

$"or:"$

$A=(-6,-2)" ; "B=(-5,-4)$
$Delta x=sqrt((-5+6)^2+(-4+2)^2)$

$Delta x=sqrt(1^2+(-2)^2)=sqrt(1+4)=sqrt5$

$Delta t=3" "s$

$v_"AB"=(Delta x)/(Delta t)$

$v_"AB"=sqrt5/3 " "m/s$

Objects A and B are at the origin. If object A moves to (-6 ,-2 )(-6 ,-2 ) and object B moves to (-5 ,-4 )(-5 ,-4 ) over 3 s3 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.