Objects A and B are at the origin. If object A moves to $(- 5, - 3)$ $(-5 ,-3 )$ and object B moves to $(- 1, - 8)$ $(-1 ,-8 )$ over $4 s$ $4 s$ , what is the relative velocity of object B from the perspective of object A?

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Objects A and B are at the origin. If object A moves to $(- 5, - 3)$ $(-5 ,-3 )$ and object B moves to $(- 1, - 8)$ $(-1 ,-8 )$ over $4 s$ $4 s$ , what is the relative velocity of object B from the perspective of object A?

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Answer 1 · 2016-04-17T19:00:33

$v = 1, 6 \frac{u n i t}{s}$ $v=1,6 " "(unit)/s$
$∠ = 308, 66^{o}$ $angle=308,66 ^o$
$you can find from the triangle of ABC (tan A)$ $"you can find from the triangle of ABC" ( tan A)"$

Explanation:

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$the green vector shows displacement for the object B from$ $"the green vector shows displacement for the object B from"$
$the perspective of A$ $"the perspective of A"$

$A B = \sqrt{{(- 1 + 5)}^{2} + {(- 8 + 3)}^{2}}$ $AB=sqrt((-1+5)^2+(-8+3)^2$

$A B = \sqrt{4^{2} + {(- 5)}^{2}}$ $AB=sqrt(4^2+(-5)^2)$

$A B = \sqrt{16 + 25}$ $AB=sqrt(16+25)$
$A B = \sqrt{41}$ $AB=sqrt41$

$A B = 6, 40 unit$ $AB=6,40 " unit"$

$v = \frac{6, 40}{4}$ $v=(6,40)/4$

$v = 1, 6 \frac{u n i t}{s}$ $v=1,6 " "(unit)/s$

$∠ = 308, 66^{o}$ $angle=308,66 ^o$
$you can find from the triangle of ABC (tan A)$ $"you can find from the triangle of ABC" ( tan A)"$

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Objects A and B are at the origin. If object A moves to $(- 5, - 3)$ $(-5 ,-3 )$ and object B moves to $(- 1, - 8)$ $(-1 ,-8 )$ over $4 s$ $4 s$ , what is the relative velocity of object B from the perspective of object A?

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Objects A and B are at the origin. If object A moves to (-5 ,-3 )(−5,−3)(-5 ,-3 ) and object B moves to (-1 ,-8 )(−1,−8)(-1 ,-8 ) over 4 s4s4 s, what is the relative velocity of object B from the perspective of object A?

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Objects A and B are at the origin. If object A moves to $(- 5, - 3)$ $(-5 ,-3 )$ and object B moves to $(- 1, - 8)$ $(-1 ,-8 )$ over $4 s$ $4 s$ , what is the relative velocity of object B from the perspective of object A?