Objects A and B are at the origin. If object A moves to (-5 ,-1 )(5,1) and object B moves to (5 ,3 )(5,3) over 3 s3s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

1 Answer
Feb 25, 2016

Velocity is 3.593.59 m/s in the direction given by theta=21.8^oθ=21.8o

Explanation:

The movement of BB relative to AA is given by ((5-(-5)),(3-(-1))((5(5)),(3(1)) or (10,4)(10,4).

Converting (10,4)(10,4) to polar coordinates (r,theta)(r,θ), they are given byr=sqrt(10^2+4^2)r=102+42 and theta=tan^(-1)(4/10)θ=tan1(410) i.e. r=sqrt(116)r=116 and theta=tan^(-1)0.4θ=tan10.4

i.e. r=10.77r=10.77 and theta=21.8^oθ=21.8o

As the distance is covered in 33 seconds,

Velocity is 10.77/3=3.5910.773=3.59 m/s in the direction given by theta=21.8^oθ=21.8o