Objects A and B are at the origin. If object A moves to $(-3 ,7 )$ and object B moves to $(1 ,3 )$ over $3 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

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Answer 1 · 2018-01-19T10:20:54

The answer is $== < 4/3, -4/3> ms^-1$

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The time is $t=3s$

The absolute velocity of $A$ is $v_A=1/3* <-3, 7> = <-1, 7/3>$

The absolute velocity of $B$ is $v_B=1/3* <1, 3> = <1/3, 1>$

The relative velocity of $B$ with respect to $A$ is

$v_(B//A)=v_B-v_A$

$= <1/3, 1> - <-1, 7/3>$

$= <1/3-(-1), 1-(7/3) >$

$= < 4/3, -4/3> ms^-1$

Objects A and B are at the origin. If object A moves to (-3 ,7 )(-3 ,7 ) and object B moves to (1 ,3 )(1 ,3 ) over 3 s3 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.