Objects A and B are at the origin. If object A moves to $(- 3, - 5)$ $(-3 ,-5 )$ and object B moves to $(7, 9)$ $(7 ,9 )$ over $3 s$ $3 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

Question

1640 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-17T09:22:40

The relative velocity is $= < \frac{10}{3}, \frac{14}{3} > m s^{- 1}$ $= <10/3, 14/3> ms^-1$

![www.slideshare.net]( useruploads.socratic.org )

The absolute velocity of $A$ $A$ is $v_{A} = \frac{1}{3} < - 3, - 5 > = < - 1, - \frac{5}{3} > m s^{- 1}$ $v_A=1/3 <-3,-5> = <-1,- 5/3> ms^-1$

The absolute velocity of $B$ $B$ is $v_{B} = \frac{1}{3} < 7, 9 > = < \frac{7}{3}, 3 > m s^{- 1}$ $v_B=1/3 <7,9> = <7/3, 3> ms^-1$

The relative velocity of $B$ $B$ with respect to $A$ $A$ is

$v_{B / A} = v_{B} - v_{A}$ $v_(B//A)=v_B-v_A$

$= < \frac{7}{3}, 3 > - < - 1, - \frac{5}{3} >$ $=<7/3, 3> - <-1, -5/3>$

$= < \frac{7}{3} + 1, 3 + \frac{5}{3} >$ $= <7/3+1, 3 +5/3>$

$= < \frac{10}{3}, \frac{14}{3} > m s^{- 1}$ $= <10/3, 14/3> ms^-1$

Objects A and B are at the origin. If object A moves to (−3,−5)(-3 ,-5 ) and object B moves to (7,9)(7 ,9 ) over 3s3 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.