Objects A and B are at the origin. If object A moves to (-3 ,1 )(3,1) and object B moves to (12 ,3 )(12,3) over 3 s3s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

1 Answer
Mar 12, 2016

=1/3(15hati+2hatj)ms^-1=13(15ˆi+2ˆj)ms1

Explanation:

Velocity vector of A = vecV_A=vecr_A/t=1/3(-3hati+hatj)ms^-1VA=rAt=13(3ˆi+ˆj)ms1
Velocity vector of B = vecV_B=vecr_B/t=1/3(12hati+3hatj)ms^-1VB=rBt=13(12ˆi+3ˆj)ms1
Hence relative velocity of B from the perspective of A is
vecV_(BA)=vecV_B-vecV_A=1/3(15hati+2hatj)ms^-1VBA=VBVA=13(15ˆi+2ˆj)ms1