Objects A and B are at the origin. If object A moves to $(- 2, 7)$ $(-2 ,7 )$ and object B moves to $(7, - 5)$ $(7 ,-5 )$ over $3 s$ $3 s$ , what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.

Question

2076 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-13T14:32:46

The relative velocity is $= < 3, - 4 > m s^{- 1}$ $= <3, -4> ms^-1$

![www.slideshare.net]( useruploads.socratic.org )

The absolute velocity of $A$ $A$ is $v_{A} = \frac{1}{3} < - 2, 7 > = < - \frac{2}{3}, \frac{7}{3} > m s^{- 1}$ $v_A=1/3 <-2,7> = <-2/3, 7/3> ms^-1$

The absolute velocity of $B$ $B$ is $v_{B} = \frac{1}{3} < 7, - 5 > = < \frac{7}{3}, - \frac{5}{3} > m s^{- 1}$ $v_B=1/3 <7,-5> = <7/3, -5/3> ms^-1$

The relative velocity of $B$ $B$ with respect to $A$ $A$ is

$v_{B / A} = v_{B} - v_{A}$ $v_(B//A)=v_B-v_A$

$= < \frac{7}{3}, - \frac{5}{3} > - < - \frac{2}{3}, \frac{7}{3} >$ $=<7/3, -5/3> - <-2/3, 7/3>$

$= < \frac{7}{3} + \frac{2}{3}, - \frac{5}{3} - \frac{7}{3} >$ $= <7/3+2/3, -5/3 -7/3>$

$= < \frac{9}{3}, - \frac{12}{3} >$ $= <9/3, -12/3>$

$= < 3, - 4 > m s^{- 1}$ $= <3, -4> ms^-1$

Objects A and B are at the origin. If object A moves to (−2,7)(-2 ,7 ) and object B moves to (7,−5)(7 ,-5 ) over 3s3 s, what is the relative velocity of object B from the perspective of object A? Assume that all units are denominated in meters.