# Number of solutions of sin^2θ+3cosθ=3 in [-π,π] ?

##### 1 Answer

Jun 23, 2018

One answer: t = 0

#### Explanation:

Replace in the equation

Sine a + b + c = 0, use shortcut. The 2 real roots are:

cos x = 1 and

cos x = 1.

Unit circle gives --> t = 0, and

Inside the interval

t = 0

Check

t = 0 --> sin^2 t = 0 --> 3cos t = 3

sin^2 t + 3cos t = 0 + 3 = 3. Proved.