Need help with simplifying trig equations?

Question

It's been a while since I've done trig identities and I seem to have completely forgotten how to do them. I ask for help for someone to do the first step of each problem to help guide me towards the answer

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Answer 1 · 2017-11-06T09:42:19

See the explanation below

You need

$sin^2theta+cos^2theta=1$

$tan^2theta+1=sec^2theta$

$1+cot^2theta=csc^2theta$

$(a+b)^2=a^2+2ab+b^2$

$a^2-b^2=(a+b)(a-b)$

$(1)$

$((tantheta+1)(tantheta+1)-sec^2theta)/(tantheta)$

$=(tan^2theta+2tantheta+1-sec^2theta)/(tantheta)$

$......$

$(2)$

$(5cos^2theta+6costheta+1)/(cos^2theta-1)=((5costheta+.....)(costheta+......))/((costheta+1)(costheta-1))$

$(3)$

$(1+cottheta)(1-cottheta)-csc^2=1-cot^2theta-csc^2theta=.......$

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