Need help with simplifying trig equations?

Question

It's been a while since I've done trig identities and I seem to have completely forgotten how to do them. I ask for help for someone to do the first step of each problem to help guide me towards the answer

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Answer 1 · 2017-11-06T09:42:19

See the explanation below

You need

#sin^2theta+cos^2theta=1#

#tan^2theta+1=sec^2theta#

#1+cot^2theta=csc^2theta#

#(a+b)^2=a^2+2ab+b^2#

#a^2-b^2=(a+b)(a-b)#

#(1)#

#((tantheta+1)(tantheta+1)-sec^2theta)/(tantheta)#

#=(tan^2theta+2tantheta+1-sec^2theta)/(tantheta)#

#......#

#(2)#

#(5cos^2theta+6costheta+1)/(cos^2theta-1)=((5costheta+.....)(costheta+......))/((costheta+1)(costheta-1))#

#(3)#

#(1+cottheta)(1-cottheta)-csc^2=1-cot^2theta-csc^2theta=.......#

I have left the blanks for you to continue. If you experience any problems, contact me.