Naomi's fish is is 40 millimeters long . her guinea pig is 25 cm long.How much longer is her guinea pig than her fish?

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Answer 1 · 2018-02-20T21:35:31

$"21 cm"$

Her guinea pig is $"25 cm"$ long.

$"25 cm = 250 mm"$

Her fish is $"40 mm"$ long, so her guinea pig is longer than her fish by

$"25 cm" - "40 mm" = "250 mm" - "40 mm" = "210 mm" = "21 cm"$

Answer 2 · 2018-02-20T21:40:43

See a solution process below:

First, lets convert the length of Naomi's guinea pig from cm to mm.

$1"cm" = 10"mm"$

We can multiply each side of the equation by $color(red)(25)$ to obtain the length of the guinea pig in mm.

$color(red)(25) xx 1"cm" = color(red)(25) xx 10"mm"$

$25"cm" = 250"mm"$

Because we have a length of the guinea pig and the fish in a common metric we can subtract the two values:

$250"mm" - 40"mm" = 210"mm"$

The guinea pig is 210 millimeters longer than the fish.

Or, if we want to convert this to centimeters we can divide by 10:

$(210" millimeters")/10 = 21" centimeters"$