$Na_3N$ decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of $Na_3N$ was used (22.4 L = 1 mole of any gas) ?

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Answer 1 · 2017-07-29T16:25:35

$1.22$ mol $Na_3N$

Given: $Na_3N$ decomposes to form sodium (Na) and Nitrogen ( $N_2)$ at STP (standard temperature and pressure). At STP $22.4 L = 1$ mole of gas

First you need to write a skeleton equation and then balance it. You need to realize that nitrogen is a diatomic element $N_2$ .

skeleton equation: $" "Na_3N -> Na + N_2$

balanced: $" "2Na_3N -> 6Na + N_2$

The balanced equation gives us the mole ratio of sodium nitrate to nitrogen produced: $2/1$ .

$13.7 cancel(L N_2) xx (1 cancel(mol N_2))/(22.4 cancel(L N_2)) xx (2 mol Na_3N)/(1 cancel(mol N_2)) = 1.22" mol "Na_3N$

Na_3NNa_3N decomposes to form sodium and nitrogen gas at STP. If 13.7 L of nitrogen is produced, how many moles of Na_3NNa_3N was used (22.4 L = 1 mole of any gas) ?