Mixture containing .538mol #He# gas, .315mol #Ne# gas .103 #Ar# gas, is confined in 7.00-L vessel at #25^o#Celsius. How do you calculate partial pressure of each gas in mixture? How would you calculate the total pressure of the mixture?

1 Answer
anor277
Feb 23, 2017

#"Dalton's law of partial pressures states that........."#

Explanation:

#"Dalton's law of partial pressures states that in a gaseous"#
#"partial pressure exerted by a component gas is the same as"#
#"the pressure it would exert if it alone occupied the container."#

#"The total pressure is the sum of the individual partial pressures."#

Here #P_"Total"=P_"He"+P_"Ne"+P_"Ar"#

#=(n_"He"RT)/V+(n_"Ne"RT)/V+(n_"Ar"RT)/V#

#=(RT)/V(n_"He"+n_"Ne"+n_"Ar")#

You have the molar quantities; you have the temperature, and volume; you have #R=0.0821*L*atm*K^-1*mol^-1#. Have at it.

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