− ln |sec(θ) − tan(θ)| = ln |sec(θ) + tan(θ)| how do you verify this identity?

1 Answer
P dilip_k
Sep 25, 2017

− ln |sec(θ) − tan(θ)|

=− ln |(sec^2(θ) − tan^2(θ))/(sec(theta)+tan(theta))|

=− ln |1/(sec(theta)+tan(theta))|

=− ln 1+ln|(sec(theta)+tan(theta))|

=0+ln|(sec(theta)+tan(theta))|

= ln |sec(θ) + tan(θ)|

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