Lithium and nitrogen react to produce lithium nitride: 6Li(s) + N_2(g) -> 2Li_3N(s). How many moles of lithium nitride are produced when 0.710 mol of lithium react in this fashion?

1 Answer
Dwight
Mar 5, 2017

We will obtain 0.237 mol of Li_3N

Explanation:

Since the given information is in moles, we need only look at the ratio between the chemicals:

Six moles of Li will produce 2 moles of lithium nitride. So, the ratio is 6:2 or 3:1.

Therefore, we can set up a proportion:

(Li)/(Li_3N) = 3/1 = 0.710/x

This tells us that in the general case, we need three times as much Li as the amount of Li_3N to be produced, and that the amount of Li_3N produced in this case must be in the same ratio. so, we can solve

3/1 = 0.710/x

Cross-multiply

3x = 0.710

x= 0.710 -: 3 = 0.237 mol of Li_3N produced

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