Lim x—> infinity∞ [(³√n+1)²-(³√n)²] Answer Value ??

1 Answer
Alan N.
Jun 8, 2018

lim_(n->oo) [(root3 n +1)^2 - (root3 n)^2] ->oo

Explanation:

f(n) = [(root3 n +1)^2 - (root3 n)^2]

= (n^(2/3) + 2n^(1/3) +1) - n^(2/3)]

= 2n^(1/3) +1

lim_(n->oo) (2n^(1/3) +1) -> oo

Hence

lim_(n->oo) f(n) -> oo

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