Let vectors A=(1,0,-3) ,B=(-2,5,1) and C=(3,1,1), how do you calculate 3A-2C?

1 Answer
Jan 3, 2016

<-3,-2,-11>

Explanation:

Scalars are multiplied in.

3A=<3,0,-9>
-2C=<-6,-2,-2>

To add the vectors, simply add each component separately.

3A+(-2C)=<3-6,0-2,-9-2>
=<-3,-2,-11>