Let #sqrt(1 + sqrt(3 + sqrt(5+ sqrt(x)))) = 2# What x?

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Answer 1 · 2016-04-26T05:01:38

#x=961#

#sqrt(1+sqrt(3+sqrt(5+sqrtx)))=2#

or #1+sqrt(3+sqrt(5+sqrtx))=4#

or #sqrt(3+sqrt(5+sqrtx))=3#

or #3+sqrt(5+sqrtx)=9#

or #sqrt(5+sqrtx)=6#

or #5+sqrtx=36#

or #sqrtx=31# or #x=961#