Joshua sold his bike for 10% less than he paid for it. lf he sold the bike for $585, how much did he pay for it?

1 Answer
Nov 16, 2016

Joshua originally paid $650 for the bike.

Explanation:

The formula for determine percent change is: p = (N - O)/O * 100p=NOO100 where pp is the percent change, NN is the new price, OO is the old price. In this problem pp and NN are provided so we can substitute for these and solve for OO while keeping the equation balanced:

-10 = (585 - O)/O * 10010=585OO100

-10/100 = (585 - O)/O * 100/10010100=585OO100100

-0.1 = (585 - O)/O0.1=585OO

-0.1 = 585/O - (O)/O0.1=585OOO

-0.1 = 585/O - 10.1=585O1

-0.1 + 1 = 585/O - 1 + 10.1+1=585O1+1

0.9 = 585/O0.9=585O

(O)/0.9 0.9 = 585/O (O)/0.9O0.90.9=585OO0.9

O = 585/0.9O=5850.9

O = 650O=650