Joshua sold his bike for 10% less than he paid for it. lf he sold the bike for $585, how much did he pay for it?

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Joshua sold his bike for 10% less than he paid for it. lf he sold the bike for $585, how much did he pay for it?

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Answer 1 · 2016-11-16T13:50:10

Joshua originally paid $650 for the bike.

Explanation:

The formula for determine percent change is: $p = \frac{N - O}{O} \cdot 100$ $p = (N - O)/O * 100$ where $p$ $p$ is the percent change, $N$ $N$ is the new price, $O$ $O$ is the old price. In this problem $p$ $p$ and $N$ $N$ are provided so we can substitute for these and solve for $O$ $O$ while keeping the equation balanced:

$- 10 = \frac{585 - O}{O} \cdot 100$ $-10 = (585 - O)/O * 100$

$- \frac{10}{100} = \frac{585 - O}{O} \cdot \frac{100}{100}$ $-10/100 = (585 - O)/O * 100/100$

$- 0.1 = \frac{585 - O}{O}$ $-0.1 = (585 - O)/O$

$- 0.1 = \frac{585}{O} - \frac{O}{O}$ $-0.1 = 585/O - (O)/O$

$- 0.1 = \frac{585}{O} - 1$ $-0.1 = 585/O - 1$

$- 0.1 + 1 = \frac{585}{O} - 1 + 1$ $-0.1 + 1 = 585/O - 1 + 1$

$0.9 = \frac{585}{O}$ $0.9 = 585/O$

$\frac{O}{0.9} 0.9 = \frac{585}{O} \frac{O}{0.9}$ $(O)/0.9 0.9 = 585/O (O)/0.9$

$O = \frac{585}{0.9}$ $O = 585/0.9$

$O = 650$ $O = 650$

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Joshua sold his bike for 10% less than he paid for it. lf he sold the bike for $585, how much did he pay for it?

1 Answer

Explanation:

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