It is about vector how to find vector of AM i have AC?

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Answer 1 · 2018-05-17T10:30:19

$vec(AC)=-8i +8j+0k and vec(AM)=-6i+2j+5k$ .

Clearly, $A(8,0,0), C(0,8,0), B(8,8,0)$ .

$:. vec(AC)=C(0,8,0)-(8,0,0)=(-8,8,0)$ .

$:. vec(AC)=-8i +8j+0k$ .

Since $D$ is the midpoint of the segment $OB$ , we have,

$D=D((0+8)/2,(0+8)/2,(0+0)/2)=D(4,4,0)$ .

$:. X=X(4,4,10)$ .

Given that $M$ is the midpoint of the segment $OX$ ,

$M=M((0+4)/2,(0+4)/2,(0+10)/2)=M(2,2,5)$ .

$:. vec(AM)=(2,2,5)-(8,0,0)=(-6,2,5)$ .

$rArr vec(AM)=-6i+2j+5k$ .