Is the graph of #log(1/2)^x# always decreasing?

1 Answer
Daniel L.
Sep 20, 2016

This function is decreasing.

Explanation:

To find if the function is incresing, decreasing or constant you have to simplify it first.

#y=log(1/2)^x #

#y=log(1/2)^x=x xx log(1/2)#

From this form we see that the function is linear and its slope is #log(1/2)#. This number is negative, so the function is decreasing in all domain #RR#

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