Is the function $f (x) = {(x^{2} + 8)}^{2}$ $f(x) = (x^2+8)^2$ even, odd or neither?

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Answer 1 · 2015-09-10T21:44:46

It is even.

We show that $f (- x) = f (x)$ $f(-x)=f(x)$ hence we have

$f (- x) = {({(- x)}^{2} + 8)}^{2} = {(x^{2} + 8)}^{2} = f (x)$ $f(-x)=((-x)^2+8)^2=(x^2+8)^2=f(x)$

Is the function f(x)=(x2+8)2f(x) = (x^2+8)^2 even, odd or neither?