Is the function #f(x) = (x^2+8)^2# even, odd or neither? Precalculus Functions Defined and Notation Symmetry 1 Answer Konstantinos Michailidis Sep 10, 2015 It is even. Explanation: We show that #f(-x)=f(x)# hence we have #f(-x)=((-x)^2+8)^2=(x^2+8)^2=f(x)# Answer link Related questions What functions have symmetric graphs? What are some examples of a symmetric function? What is a line of symmetry? What is rotational symmetry? Is the function #f(x) = x^2# symmetric with respect to the y-axis? Is the function #f(x) = x^2# symmetric with respect to the x-axis? Is the function #f(x) = x^3# symmetric with respect to the y-axis? What is the line of symmetry for #f(x) = x^4#? Is the graph of the function #f(x) = 2^x# symmetric? Is #f(x)=x^2+sin x# an even or odd function? See all questions in Symmetry Impact of this question 2152 views around the world You can reuse this answer Creative Commons License