Is it possible to factor y=x^3 - 2x^2 + 3x -6 ? If so, what are the factors?
1 Answer
May 28, 2016
Explanation:
Group the terms in 'pairs' thus
[x^3-2x^2]+[3x-6] now factorise each 'pair'
x^2(x-2)+3(x-2) A common factor of (x -2) can now be removed
rArr(x-2)(x^2+3)
