Is it possible to factor #y=x^3 - 2x^2 + 3x -6 #? If so, what are the factors?
1 Answer
May 28, 2016
Explanation:
Group the terms in 'pairs' thus
#[x^3-2x^2]+[3x-6]# now factorise each 'pair'
#x^2(x-2)+3(x-2)# A common factor of (x -2) can now be removed
#rArr(x-2)(x^2+3)#
