Is it possible to factor #y=4x^2-49 #? If so, what are the factors?

1 Answer
Don't Memorise
Dec 10, 2015

# color(blue)((2x-7) , (2x+7)# are the factos of the expression.

Explanation:

#y=4x^2-49#

The expression can be re written as:
#y=(2x)^2-7^2#, this is of the below format:

#color(blue)(a^2-b^2=(a-b)(a+b)#

So,
#y=(2x)^2-7^2 = color(blue)((2x-7)(2x+7)#

# color(blue)((2x-7)(2x+7)# is the factorised form of the expression.

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