Is it possible to factor #y=3x^2+2x-8 #? If so, what are the factors?

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Answer 1 · 2018-04-19T16:37:23

#y=(x+2)(3x-4)#

#y=3x^2+2x-8#

to begin the factorising process

we look for factors of #3xx-8=-24#

that sum to the middle term #2#

by inspection we will have #+6, -4#

#we now split teh middle term with these factors and factorise by grouping

#y=3x^2+6x-4x-8#

#y=(3x^2+6x)-(4x+8)#

#y=3x(x+2)-4.(x+2)#

#y=(x+2)(3x-4)#