Is it possible for a finitelygenerated group to contain subgroups that are not finitelygenerated ? True or False. Prove your conclusion.
1 Answer
It is possible.
Explanation:
The classic example is the commutator subgroup of the free group on two generators.
Let:
#G = < a, b>#
If
#[g, h] = g^(1) h^(1) g h#
The subgroup of
We can make things simpler by specifying the subgroup
Any element of
Given a product of

Strip out any elementinverse element pairs to reduce the product to minimum form, i.e. get rid of combinations like
#a a^(1)# or#b^(1) b# . 
The cleaned up form will start with a block of
#a^(1)# 's or#b^(1)# 's. The length of this block allows you to identify the first commutator in a representation as a product of commutators of the form#[a^n, b^n]# and/or#[b^n, a^n]# . 
The end of the commutator may require some elementinverse element pairs to be added in order to reconstitute it. Add just as many as necessary before splitting off the first commutator.

Repeat with the remainder of the product to recover the remaining commutators.

Once all commutators have been recovered, strip out any adjacent pairs of commutators of the form
#[a^n, b^n][b^n, a^n]# or#[b^n, a^n][a^n b^n]# to reduce to the minimum representation.
Hence we find that