Is #2pi*sqrt(l/g)# reducable to a dimension of time?

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Answer 1 · 2016-03-18T13:21:53

Yes. Yes it is.

This equation is the period of a simple pendulum. Assuming your #l# stands for length, and #g# stands for gravity, we can rewrite this problem as

Period #= 2pi*sqrt(L/(L/T^2))#

Rewriting your fraction inside the #sqrt()# symbol,

Period #=2pi*sqrt(L*T^2/L)#

Cancelling terms and knowing that square roots cancel powers of 2, we get,

Period #=2pi*T#

So yes, this equation is reducible to a unit of time.