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Iron (III) oxide reacts with carbon monoxide to form molten iron and carbon dioxide. If .18 g of iron (III) oxide reacts with 0.11 g of carbon monoxide, how many grams of iron would be produced?

1 Answer

May 20, 2016

#Fe_2O_3(s) + 3CO(g) rarr 2Fe(l) + 3CO_2(g)#

Explanation:

#"Moles of ferric oxide "=(0.18*g)/(159.69*g*mol^-1)# #=# #1.13xx10^-3*mol" metal oxide"#.

#"Moles of carbon monoxide "=(0.11*g)/(28.0*g*mol^-1)# #=# #3.93xx10^-3*mol" CO"#.

#Fe_2O_3# is the reagent in deficiency (why?), and thus #2xx1.13xx10^-3*molxx55.85*g*mol^-1~=0.150*g# iron metal are produced.

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