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Integrate (sin 2pi*t)÷T from 0 to T÷2 ?

1 Answer

Apr 27, 2018

The answer #(-cos(2pit)-1)/(2pi)#

Explanation:

if your question was
#int_0^(t/2)sin2pit*dt#

#int_0^(t/2)sin2pit*dt=(-1/(2pi))int_0^(t/2)-2pi*sin(2pit)*dt#

#(-1/(2pi))[cos(2pi)]_0^(t/2)=(-cos(2pit)-1)/(2pi)#

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