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#int(3x^-7+x^-1)dx#. Evaluate?

1 Answer

Apr 12, 2018

#-3/8x^-8+ln|x|+C#

Explanation:

Given: #int(3x^-7+x^-1) \ dx#

#=int3x^-7 \ dx+intx^-1 \ dx#

#=-3/8x^-8+int1/x \ dx#

#=-3/8x^-8+ln|x|#

Adding a constant,

#=-3/8x^-8+ln|x|+C#

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