In triangle ABC, <A=84.2°, <B=20.7°, B=17.2 how do you find side C? Trigonometry Triangles and Vectors The Law of Cosines 1 Answer salamat Feb 6, 2017 #C = 47.02 u# Explanation: The angle of #C = 180^o-84.2^o-20.7^o=75.1^o# #C/sin C^o=B/sin B^o# #C/sin 75.1^o = 17.2/sin 20.7^o# #C/0.9664 = 17.2/0.3535# #C = 17.2/0.3535*0.9664# #C = 47.02 u# Answer link Related questions Does the law of cosines work for any triangle? How do you derive the law of cosines? How is the law of cosines related to the pythagorean theorem? How do you find the angle in the law of cosines? How do you use the law of cosines to find the area of a triangle? What is the law of cosines? When can the law of cosines be used? How do you find angles A, B, and C if in triangle ABC, #a=12#, #b=15#, and #c=20#? How do you find the measure of the smallest in an acute triangle whose side lengths are 4m, 7m, and 8m? Bong walks 100 m due North and then 150 m in a direction N 37 deg. E. How far is Bong from his... See all questions in The Law of Cosines Impact of this question 1244 views around the world You can reuse this answer Creative Commons License