In triangle ABC, a=6.3. B=9.4, <C=38.3° how do you find side C ?

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Answer 1 · 2016-07-09T20:36:54

First, let's draw a diagram.

enter image source here

Cosine's Law states that #c^2 = a^2 + b^2 - 2abcosC#

Hence,

#c^2 = 6.3^2 + 9.4^2 - (2 xx 6.3 xx 9.4 xx cos(38.3˚))#

#c = 5.9#

#:.#Side C measures #5.9# units.

Hopefully this helps!