In $triangle ABC, a=5, b=12, c=13$ , how do you find the cosine of each of the angles?

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Answer 1 · 2017-07-22T03:11:57

Since $5^2+12^2 = 13^2$ , this is a right triangle with hypotenuse $c=13$ .

$cos A =b/c = 12/13$

$cos B = a/c = 5/13$

$cosC = cos90^@ = 0$

In triangle ABC, a=5, b=12, c=13triangle ABC, a=5, b=12, c=13, how do you find the cosine of each of the angles?